About Lesson
7.3 Parametric Equations and Locus 参数方程式与轨迹
(1)
Find the equation of the locus of the centers of circles passing through the points of intersection of the circle x + y – 2x – 4y – 11 = 0 and the line y = x + 3.
求经过圆x + y – 2x – 4y – 11 = 0及直线y = x + 3的交点的圆之圆心的轨迹方程式.
Answer :
x + y = 3
(2)
A variable circle touches the y-axis, and also touches a fixed circle x + y – 8x + 2y + 13 = 0 externally. Find the equation of the locus of the centre of the circle.
A variable circle touches the y-axis, and also touches a fixed circle x + y – 8x + 2y + 13 = 0 externally. Find the equation of the locus of the centre of the circle.
一动圆与y轴相切, 且与圆x + y – 8x + 2y + 13 = 0外切. 求其圆心的轨迹方程式
Answer :
y – 12x + 2y + 13 = 0
(3)
Find the equation of the locus of the centers of the circles that orthogonal with x + y – 6x + 4y + 5 = 0 and x + y + 2x – 9 = 0.
Find the equation of the locus of the centers of the circles that orthogonal with x + y – 6x + 4y + 5 = 0 and x + y + 2x – 9 = 0.
一圆与二已知圆x + y – 6x + 4y + 5 = 0 及 x + y + 2x – 9 = 0正交, 试求此圆圆心的轨迹的方程式
Answer :
4x – 2y – 7 = 0
(4)
The equation x + y + ax + by + 7 = 0 represents a unit circle. Find the equation of the locus of its centre as a, b vary.
The equation x + y + ax + by + 7 = 0 represents a unit circle. Find the equation of the locus of its centre as a, b vary.
若 x + y + ax + by + 7 = 0 为一单位圆。当a, b 改変时求圆心的轨迹方程式。
Answer :
x + y = 8
(5)
A straight line through the point (0,1) meets the circle C : x + y – 2x – 4y + 4 = 0 at points P, P such that the slope of PP is k. Find the equation of the locus of the mid-point of PP, as k varies.
A straight line through the point (0,1) meets the circle C : x + y – 2x – 4y + 4 = 0 at points P, P such that the slope of PP is k. Find the equation of the locus of the mid-point of PP, as k varies.
一经过点(0, 1)的直线与圆 x + y – 2x – 4y + 4 = 0 交于点 P, P 且 PP 斜率为k。當k改変时, 求 PP 中点轨迹方程式。
Answer :
x + y – x – 3y + 2 = 0